b^2-11b^2=-10

Solution for b^2-11b^2=-10 equation:

b^2-11b^2=-10

We move all terms to the left:

b^2-11b^2-(-10)=0

We add all the numbers together, and all the variables

-10b^2+10=0

a = -10; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-10)·10
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*-10}=\frac{-20}{-20}
=1
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*-10}=\frac{20}{-20}
=-1
$